-13.57+1.057x-0.01x^2=0

Solution for -13.57+1.057x-0.01x^2=0 equation:

-13.57+1.057x-0.01x^2=0

a = -0.01; b = 1.057; c = -13.57;
Δ = b2-4ac
Δ = 1.0572-4·(-0.01)·(-13.57)
Δ = 0.574449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.057)-\sqrt{0.574449}}{2*-0.01}=\frac{-1.057-\sqrt{0.574449}}{-0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.057)+\sqrt{0.574449}}{2*-0.01}=\frac{-1.057+\sqrt{0.574449}}{-0.02}
$